What is the derivative of 2x^7-3x^4+4x^3-12x+4 ?

The derivative of 2x^7-3x^4+4x^3-12x+4 is 14x^6-12x^3+12x^2-12

What is the first derivative of 2x^7-3x^4+4x^3-12x+4 ?

The first derivative of 2x^7-3x^4+4x^3-12x+4 is 14x^6-12x^3+12x^2-12

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\frac{d}{d x} (2 x^{7} - 3 x^{4} + 4 x^{3} - 12 x + 4)

14 x^{6} - 12 x^{3} + 12 x^{2} - 12

Solution steps

\frac{d}{d x} (2 x^{7} - 3 x^{4} + 4 x^{3} - 12 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{7}) - \frac{d}{d x} (3 x^{4}) + \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (12 x) + \frac{d}{d x} (4)

\frac{d}{d x} (2 x^{7}) = 14 x^{6}

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (12 x) = 12

\frac{d}{d x} (4) = 0

= 14 x^{6} - 12 x^{3} + 12 x^{2} - 12 + 0

Simplify

= 14 x^{6} - 12 x^{3} + 12 x^{2} - 12

\frac{d}{d x} (\frac{1 - sin ( x )}{1 + cos ( x )})

\frac{d}{d x} (x cos (y))

\int_{0}^{10} 2200 e^{0.024 x} - 1460 e^{0.018 x} d x

\int \frac{1}{T} d T

n = 1 \sum \infty \frac{1}{n - 1}

What is the derivative of 2x^7-3x^4+4x^3-12x+4 ?
The derivative of 2x^7-3x^4+4x^3-12x+4 is 14x^6-12x^3+12x^2-12
What is the first derivative of 2x^7-3x^4+4x^3-12x+4 ?
The first derivative of 2x^7-3x^4+4x^3-12x+4 is 14x^6-12x^3+12x^2-12