What is the integral from 0 to 10 of 2200e^{0.024x}-1460e^{0.018x} ?

The integral from 0 to 10 of 2200e^{0.024x}-1460e^{0.018x} is 8867.98599…

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integral from 0 to 10 of 2200e^{0.024x}-1460e^{0.018x}

\int_{0}^{10} 2200 e^{0.024 x} - 1460 e^{0.018 x} d x

8867.98599 \dots

Solution steps

\int_{0}^{10} 2200 e^{0.024 x} - 1460 e^{0.018 x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{10} 2200 e^{0.024 x} d x - \int_{0}^{10} 1460 e^{0.018 x} d x

\int_{0}^{10} 2200 e^{0.024 x} d x = 24864.50544 \dots

\int_{0}^{10} 1460 e^{0.018 x} d x = 15996.51945 \dots

= 24864.50544 \dots - 15996.51945 \dots

Simplify

= 8867.98599 \dots

\int \frac{1}{T} d T

n = 1 \sum \infty \frac{1}{n - 1}

\frac{1 - 4 t}{1 + 3 t}

x \to 1 lim (1 + cos (π) x)

\int_{0}^{1} (2 t - 1)^{2} d t

What is the integral from 0 to 10 of 2200e^{0.024x}-1460e^{0.018x} ?
The integral from 0 to 10 of 2200e^{0.024x}-1460e^{0.018x} is 8867.98599…