What is the derivative of (2x/((x+1)^2)) ?

The derivative of (2x/((x+1)^2)) is (2(1-x))/((x+1)^3)

What is the first derivative of (2x/((x+1)^2)) ?

The first derivative of (2x/((x+1)^2)) is (2(1-x))/((x+1)^3)

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\frac{d}{d x} (\frac{2 x}{( x + 1 ) ^{2}})

\frac{2 ( 1 - x )}{( x + 1 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{2 x}{( x + 1 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{x}{( x + 1 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 2 \cdot \frac{\frac{d x}{d x} ( x + 1 ) ^{2} - \frac{d}{d x} ( ( x + 1 ) ^{2} ) x}{( ( x + 1 ) ^{2} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} ((x + 1)^{2}) = 2 (x + 1)

= 2 \cdot \frac{1 \cdot ( x + 1 ) ^{2} - 2 ( x + 1 ) x}{( ( x + 1 ) ^{2} ) ^{2}}

Simplify

2 \cdot \frac{1 \cdot ( x + 1 ) ^{2} - 2 ( x + 1 ) x}{( ( x + 1 ) ^{2} ) ^{2}} : \frac{2 ( 1 - x )}{( x + 1 ) ^{3}}

= \frac{2 ( 1 - x )}{( x + 1 ) ^{3}}

\frac{d}{d x} (3 x^{2} - 7 x + 10)

f (x) = 2 x^{2} + 5 x - 3

\int \frac{1}{( x ^{2} - 1 ) ( x - 3 )} d x

\int 2 x - 2 d x

y^{^{'}} + \frac{y}{t} = t^{2} y^{4}

What is the derivative of (2x/((x+1)^2)) ?
The derivative of (2x/((x+1)^2)) is (2(1-x))/((x+1)^3)
What is the first derivative of (2x/((x+1)^2)) ?
The first derivative of (2x/((x+1)^2)) is (2(1-x))/((x+1)^3)