What is (\partial)/(\partial x)(7e^{xy+5}) ?

The answer to (\partial)/(\partial x)(7e^{xy+5}) is 7e^{xy+5}y

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(\partial)/(\partial x)(7e^{xy+5})

\frac{\partial}{\partial x} (7 e^{x y + 5})

7 e^{x y + 5} y

Solution steps

\frac{\partial}{\partial x} (7 e^{x y + 5})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{\partial}{\partial x} (e^{x y + 5})

Apply the chain rule:

e^{x y + 5} \frac{\partial}{\partial x} (x y + 5)

= e^{x y + 5} \frac{\partial}{\partial x} (x y + 5)

\frac{\partial}{\partial x} (x y + 5) = y

= 7 e^{x y + 5} y

\int \frac{( cos ( 2 x ) - 1 )}{cos ( 2 x ) + 1} d x

(- \frac{10}{63}, \frac{1}{3}), (\frac{2}{3}, - \frac{11}{45})

f (x) = \frac{( 2 - e ^{x} + 2 x )}{3}

\int x y d x

(7, - 7), (5, - 3)

What is (\partial)/(\partial x)(7e^{xy+5}) ?
The answer to (\partial)/(\partial x)(7e^{xy+5}) is 7e^{xy+5}y