What is the solution for y'=0.1*y*(1-y/(80)) ?

The solution for y'=0.1*y*(1-y/(80)) is y=-(80e^{0.1t+c_{1}})/(1-e^{0.1t+c_{1)}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y'=0.1y(1-y/(80))

y^{^{'}} = 0.1 \cdot y \cdot (1 - \frac{y}{80})

y = - \frac{80 e ^{0.1 t + c_{1}}}{1 - e ^{0.1 t + c_{1}}}

Solution steps

y^{'} (t) = 0.1 \cdot y \cdot (1 - \frac{y}{80})

Solve separable ODE:

y = - \frac{80 e ^{0.1 t + c_{1}}}{1 - e ^{0.1 t + c_{1}}}

y = - \frac{80 e ^{0.1 t + c_{1}}}{1 - e ^{0.1 t + c_{1}}}

y^{^{'}} = \frac{e ^{x} - e ^{- x}}{3 + 4 y}

\int e^{- αx} d x

\int_{- 2}^{0} (2 x + 5) d x

\frac{d}{d x} (3 x^{2} - 4 x + 5)

\int_{- 1}^{1} \frac{1}{1 + x ^{2}} d x

What is the solution for y'=0.1*y*(1-y/(80)) ?
The solution for y'=0.1*y*(1-y/(80)) is y=-(80e^{0.1t+c_{1}})/(1-e^{0.1t+c_{1)}}