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Popular >

integral from-2 to 0 of (2x+5)

Solution

\int_{- 2}^{0} (2 x + 5) d x

Solution

6

Solution steps

\int_{- 2}^{0} 2 x + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{0} 2 x d x + \int_{- 2}^{0} 5 d x

\int_{- 2}^{0} 2 x d x = - 4

\int_{- 2}^{0} 5 d x = 10

= - 4 + 10

Simplify

= 6

Popular Examples

derivative of 3x^2-4x+5

\frac{d}{d x} (3 x^{2} - 4 x + 5)

integral from-1 to 1 of 1/(1+x^2)

\int_{- 1}^{1} \frac{1}{1 + x ^{2}} d x

ty^'+4y=t^2-t+7

t y^{^{'}} + 4 y = t^{2} - t + 7

laplacetransform t^2sin^2(t)laplace transform

t^{2} sin^{2} (t)

(dy)/(dx)= x/(25y),y(0)=-5

\frac{d y}{d x} = \frac{x}{25 y}, y (0) = - 5

Frequently Asked Questions (FAQ)

What is the integral from-2 to 0 of (2x+5) ?
The integral from-2 to 0 of (2x+5) is 6