What is the solution for y^'+3(tan(3x))y=cos(3x) ?

The solution for y^'+3(tan(3x))y=cos(3x) is y= x/(sec(3x))+(c_{1})/(sec(3x))

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y^'+3(tan(3x))y=cos(3x)

y^{^{'}} + 3 (tan (3 x)) y = cos (3 x)

y = \frac{x}{sec ( 3 x )} + \frac{c _{1}}{sec ( 3 x )}

Solution steps

y^{'} (x) + 3 (tan (3 x)) y = cos (3 x)

Solve linear ODE:

y = \frac{x}{sec ( 3 x )} + \frac{c _{1}}{sec ( 3 x )}

y = \frac{x}{sec ( 3 x )} + \frac{c _{1}}{sec ( 3 x )}

\frac{( 12 s + 5 )}{s ( s + 3 )}

\frac{1}{x ^{2}} - \frac{7}{x ^{4}}

\int (2 x - 3) e^{x^{2} - 3 x} d x

\frac{d}{d x} (5 ln (2 + x))

x \to 1 lim (\frac{x ^{3} - 1}{x + 1})

What is the solution for y^'+3(tan(3x))y=cos(3x) ?
The solution for y^'+3(tan(3x))y=cos(3x) is y= x/(sec(3x))+(c_{1})/(sec(3x))