What is the integral of (2x-3)e^{x^2-3x} ?

The integral of (2x-3)e^{x^2-3x} is e^{x^2-3x}+C

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integral of (2x-3)e^{x^2-3x}

\int (2 x - 3) e^{x^{2} - 3 x} d x

e^{x^{2} - 3 x} + C

Solution steps

\int (2 x - 3) e^{x^{2} - 3 x} d x

Apply u-substitution

: \int e^{u} d u

= \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= e^{u}

Substitute back

u = x^{2} - 3 x

= e^{x^{2} - 3 x}

Add a constant to the solution

= e^{x^{2} - 3 x} + C

\frac{d}{d x} (5 ln (2 + x))

x \to 1 lim (\frac{x ^{3} - 1}{x + 1})

\int (6 x^{2}) d x

\frac{d}{d x} (\frac{x ^{2} + 3}{cos ( x )})

y = arctan (\frac{x}{4}), (4, \frac{π}{4})

What is the integral of (2x-3)e^{x^2-3x} ?
The integral of (2x-3)e^{x^2-3x} is e^{x^2-3x}+C