What is the integral of 2x^3e^{x^2} ?

The integral of 2x^3e^{x^2} is e^{x^2}x^2-e^{x^2}+C

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integral of 2x^3e^{x^2}

\int 2 x^{3} e^{x^{2}} d x

e^{x^{2}} x^{2} - e^{x^{2}} + C

Solution steps

\int 2 x^{3} e^{x^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int x^{3} e^{x^{2}} d x

Apply u-substitution

: \int \frac{e ^{u^{\frac{2}{3}}} u ^{\frac{1}{3}}}{3} d u

= 2 \cdot \int \frac{e ^{u^{\frac{2}{3}}} u ^{\frac{1}{3}}}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{3} \cdot \int e^{u^{\frac{2}{3}}} u^{\frac{1}{3}} d u

Apply u-substitution

: \int \frac{3 e ^{v} v}{2} d v

= 2 \cdot \frac{1}{3} \cdot \int \frac{3 e ^{v} v}{2} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{3} \cdot \frac{3}{2} \cdot \int e^{v} v d v

Apply Integration By Parts

: e^{v} v - \int e^{v} d v

= 2 \cdot \frac{1}{3} \cdot \frac{3}{2} (e^{v} v - \int e^{v} d v)

\int e^{v} d v = e^{v}

= 2 \cdot \frac{1}{3} \cdot \frac{3}{2} (e^{v} v - e^{v})

Substitute back

= 2 \cdot \frac{1}{3} \cdot \frac{3}{2} (e^{(x^{3})^{\frac{2}{3}}} (x^{3})^{\frac{2}{3}} - e^{(x^{3})^{\frac{2}{3}}})

Simplify

2 \cdot \frac{1}{3} \cdot \frac{3}{2} (e^{(x^{3})^{\frac{2}{3}}} (x^{3})^{\frac{2}{3}} - e^{(x^{3})^{\frac{2}{3}}}) : e^{x^{2}} x^{2} - e^{x^{2}}

= e^{x^{2}} x^{2} - e^{x^{2}}

Add a constant to the solution

= e^{x^{2}} x^{2} - e^{x^{2}} + C

\frac{d}{d x} (x + y - 1)

\int (\frac{1}{2 x}) d x

y = 3 x, x = 0, x = 4

2^{y}

f (x) = (2 x - 1)^{3}, at x = 1

What is the integral of 2x^3e^{x^2} ?
The integral of 2x^3e^{x^2} is e^{x^2}x^2-e^{x^2}+C