What is the solution for y^{''}+10y^'+34y=0 ?

The solution for y^{''}+10y^'+34y=0 is y=e^{-5t}(c_{1}cos(3t)+c_{2}sin(3t))

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y^{''}+10y^'+34y=0

y^{^{''}} + 10 y^{^{'}} + 34 y = 0

y = e^{- 5 t} (c_{1} cos (3 t) + c_{2} sin (3 t))

Solution steps

y^{''} (t) + 10 y^{'} (t) + 34 y = 0

Solve linear ODE:

y = e^{- 5 t} (c_{1} cos (3 t) + c_{2} sin (3 t))

y = e^{- 5 t} (c_{1} cos (3 t) + c_{2} sin (3 t))

x d y - y d x = 2 x^{2} y^{2} d y, y (1) = 2

\frac{d}{d x} (cos (2 x) cos (x))

\int \frac{8 - 3 x}{25 - 64 x ^{2}} d x

(x - 3) (x^{2} + 6)

\frac{\partial}{\partial x} (8 x cos (x) cos (y))

What is the solution for y^{''}+10y^'+34y=0 ?
The solution for y^{''}+10y^'+34y=0 is y=e^{-5t}(c_{1}cos(3t)+c_{2}sin(3t))