What is the limit as x approaches+3 of 8/(x-3) ?

The limit as x approaches+3 of 8/(x-3) is diverges

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limit as x approaches+3 of 8/(x-3)

x \to + 3 lim (\frac{8}{x - 3})

diverges

Solution steps

x \to 3 lim (\frac{8}{x - 3})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 3 + lim (\frac{8}{x - 3}) = \infty

x \to 3 - lim (\frac{8}{x - 3}) = - \infty

= diverges

5 x, \frac{5}{x}, 0, 5

\int_{0}^{\frac{π}{4}} 6 tan^{3} (x) d x

\frac{\partial}{\partial y} ((2 x - y + 5)^{2})

f (x) = (4 x^{2} - 5 x) e^{x}

\int 5 e^{- 4 x} d x

What is the limit as x approaches+3 of 8/(x-3) ?
The limit as x approaches+3 of 8/(x-3) is diverges