What is the derivative of 5x^{-2}+500 ?

The derivative of 5x^{-2}+500 is -(10)/(x^3)

What is the first derivative of 5x^{-2}+500 ?

The first derivative of 5x^{-2}+500 is -(10)/(x^3)

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\frac{d}{d x} (5 x^{- 2} + 500)

- \frac{10}{x ^{3}}

Solution steps

\frac{d}{d x} (5 x^{- 2} + 500)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x^{- 2}) + \frac{d}{d x} (500)

\frac{d}{d x} (5 x^{- 2}) = - \frac{10}{x ^{3}}

\frac{d}{d x} (500) = 0

= - \frac{10}{x ^{3}} + 0

Simplify

= - \frac{10}{x ^{3}}

\int x^{5} I n (x) d x

\frac{d ^{2}}{d x ^{2}} (8 x^{- 2})

\int (2 x^{2} + x) \cdot e^{- 3 x} d x

\frac{d}{d x} (- ln (2 x - 3))

y = 2 x^{3} - x^{2} + 4, (2, 16)

What is the derivative of 5x^{-2}+500 ?
The derivative of 5x^{-2}+500 is -(10)/(x^3)
What is the first derivative of 5x^{-2}+500 ?
The first derivative of 5x^{-2}+500 is -(10)/(x^3)