What is the sum from n=1 to infinity}((-3)^{n-1 of)/(8^n) ?

The sum from n=1 to infinity}((-3)^{n-1 of)/(8^n) is converges

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sum from n=1 to infinity}((-3)^{n-1 of)/(8^n)

n = 1 \sum \infty \frac{( - 3 ) ^{n - 1}}{8 ^{n}}

converges

Solution steps

n = 1 \sum \infty \frac{( - 3 ) ^{n - 1}}{8 ^{n}}

Apply Series Ratio Test:

converges

= converges

\frac{\partial}{\partial x} (4 (x - 1)^{2})

n = 1 \sum \infty n sin (\frac{1}{n})

\frac{\partial}{\partial x} (2 + 3 x + 4 y)

\int_{0}^{2} (4 - x^{2}) d x

\frac{2 s}{s ^{2} + 8 s + 25}

What is the sum from n=1 to infinity}((-3)^{n-1 of)/(8^n) ?
The sum from n=1 to infinity}((-3)^{n-1 of)/(8^n) is converges