What is (\partial)/(\partial x)(3cos^2(x)) ?

The answer to (\partial)/(\partial x)(3cos^2(x)) is -3sin(2x)

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(\partial)/(\partial x)(3cos^2(x))

\frac{\partial}{\partial x} (3 cos^{2} (x))

- 3 sin (2 x)

Solution steps

\frac{\partial}{\partial x} (3 cos^{2} (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{\partial}{\partial x} (cos^{2} (x))

Apply the chain rule:

2 cos (x) \frac{\partial}{\partial x} (cos (x))

= 2 cos (x) \frac{\partial}{\partial x} (cos (x))

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= 3 \cdot 2 cos (x) (- sin (x))

Simplify

3 \cdot 2 cos (x) (- sin (x)) : - 3 sin (2 x)

= - 3 sin (2 x)

\int lo g_{8} (3 x) d x

\int_{1}^{9} x d x

\int (\frac{1}{cos ( 4 x )})^{2} d x

y^{'} = 0.0012 y (1000 - y)

\int 2 e^{2 θ} sin (2 θ) d θ

What is (\partial)/(\partial x)(3cos^2(x)) ?
The answer to (\partial)/(\partial x)(3cos^2(x)) is -3sin(2x)