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Popular >

x^2y^'=-2xy+(y)^2

Solution

x^{2} y^{^{'}} = - 2 x y + (y)^{2}

Solution

y = \frac{3 x}{1 + 3 c _{1} x ^{3}}

Solution steps

x^{2} y^{'} (x) = - 2 x y + (y)^{2}

Solve Bernoulli ODE:

y = \frac{3 x}{1 + 3 c _{1} x ^{3}}

y = \frac{3 x}{1 + 3 c _{1} x ^{3}}

Popular Examples

tangent of f(x)=3x^2,\at x=10 tangent of

f (x) = 3 x^{2}, at x = 10

integral from 1 to 10 of (37)/(x^3)

\int_{1}^{10} \frac{37}{x ^{3}} d x

derivative of ln((2x+1/(2x-1)))

\frac{d}{d x} (ln (\frac{2 x + 1}{2 x - 1}))

limit as x approaches a of 1-sqrt(1-x^2)

x \to a lim (1 - 1 - x^{2})

(dy)/(dx)=e^{(6y+3x)}

\frac{d y}{d x} = e^{(6 y + 3 x)}

Frequently Asked Questions (FAQ)

What is the solution for x^2y^'=-2xy+(y)^2 ?
The solution for x^2y^'=-2xy+(y)^2 is y=(3x)/(1+3c_{1)x^3}