What is the limit as x approaches 0 of 1+sin^2(3x) ?

The limit as x approaches 0 of 1+sin^2(3x) is 1

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limit as x approaches 0 of 1+sin^2(3x)

x \to 0 lim (1 + sin^{2} (3 x))

1

Solution steps

x \to 0 lim (1 + sin^{2} (3 x))

Plug in the value

x = 0

= 1 + sin^{2} (3 \cdot 0)

Simplify

1 + sin^{2} (3 \cdot 0) : 1

= 1

\frac{d ^{2}}{d x ^{2}} (sin (x) cos (x))

\int (\frac{( x - 3 )}{( x + 2 )}) d x

\frac{\partial}{\partial x} (9)

y^{^{'}} = a^{x + y}

\int \frac{x}{x - x ^{2}} d x

What is the limit as x approaches 0 of 1+sin^2(3x) ?
The limit as x approaches 0 of 1+sin^2(3x) is 1