What is the integral of (t^2+t)e^{t^3+3t} ?

The integral of (t^2+t)e^{t^3+3t} is (t+t^2)e^{t^3+3t}x+C

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integral of (t^2+t)e^{t^3+3t}

\int (t^{2} + t) e^{t^{3} + 3 t} d x

(t + t^{2}) e^{t^{3} + 3 t} x + C

Solution steps

\int (t^{2} + t) e^{t^{3} + 3 t} d x

Integral of a constant:

\int a d x = a x

= (t + t^{2}) e^{t^{3} + 3 t} x

Add a constant to the solution

= (t + t^{2}) e^{t^{3} + 3 t} x + C

y^{^{'}} + 3 y = 2

\int_{1}^{2} (\frac{2}{x ^{3}}) d x

f (x) = ln (x^{3} - 1)

x 64 - x^{2}, 0

\int - cos (\frac{x}{2}) d x

What is the integral of (t^2+t)e^{t^3+3t} ?
The integral of (t^2+t)e^{t^3+3t} is (t+t^2)e^{t^3+3t}x+C