What is the derivative of f(x)=4x^2-1 ?

The derivative of f(x)=4x^2-1 is 8x

What is the first derivative of f(x)=4x^2-1 ?

The first derivative of f(x)=4x^2-1 is 8x

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derivative of

f (x) = 4 x^{2} - 1

8 x

Solution steps

\frac{d}{d x} (4 x^{2} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) - \frac{d}{d x} (1)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (1) = 0

= 8 x - 0

Simplify

= 8 x

y = (1 + 5 x)^{12}, (0, 1)

x y^{^{'}} + 2 y = 2 e^{x}

\frac{d x}{d t} = sin (x)

\int e^{\frac{x}{16}} d x

\int x^{2} (x - 7) d x

What is the derivative of f(x)=4x^2-1 ?
The derivative of f(x)=4x^2-1 is 8x
What is the first derivative of f(x)=4x^2-1 ?
The first derivative of f(x)=4x^2-1 is 8x