What is the integral from 0 to 27 of 1/(\sqrt[3]{x)} ?

The integral from 0 to 27 of 1/(\sqrt[3]{x)} is 27/2

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integral from 0 to 27 of 1/(\sqrt[3]{x)}

\frac{27}{2}

Solution steps

Apply the Power Rule

: [\frac{3}{2} x^{\frac{2}{3}}]_{0}^{27}

= [\frac{3}{2} x^{\frac{2}{3}}]_{0}^{27}

Compute the boundaries:

\frac{27}{2}

= \frac{27}{2}

sin (3 t)

\frac{\partial ^{2}}{\partial r \partial θ} (r (θ) sin (θ))

\int_{- 1}^{1} (x^{2} - 2 x) d x

\frac{d}{d x} (\frac{sin ( 2 x )}{cos ( x ^{2} )})

\int - \frac{1}{z ^{2}} d z

What is the integral from 0 to 27 of 1/(\sqrt[3]{x)} ?
The integral from 0 to 27 of 1/(\sqrt[3]{x)} is 27/2