What is the solution for f^'(x)=((6tan(x)+2))/(sec(x)) ?

The solution for f^'(x)=((6tan(x)+2))/(sec(x)) is f(x)=-6cos(x)+2sin(x)+c_{1}

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f^'(x)=((6tan(x)+2))/(sec(x))

f^{^{'}} (x) = \frac{( 6 tan ( x ) + 2 )}{sec ( x )}

f (x) = - 6 cos (x) + 2 sin (x) + c_{1}

Solution steps

f^{'} (x) = \frac{( 6 tan ( x ) + 2 )}{sec ( x )}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int \frac{6 tan ( x ) + 2}{sec ( x )} d x

\int \frac{6 tan ( x ) + 2}{sec ( x )} d x = - 6 cos (x) + 2 sin (x) + c_{1}

f (x) = - 6 cos (x) + 2 sin (x) + c_{1}

n = 0 \sum \infty 2 n^{2} + 1

(e^{t} sin (t))^{^{'}}

\frac{\partial}{\partial v} (u (v) (v)^{2 v} + e^{3})

y^{^{''}} - 4 y^{^{'}} + 4 y = 0, y (0) = - 2, y^{^{'}} (0) = 2

\frac{d}{d x} (x^{3} - 2 x^{2} + 1)

What is the solution for f^'(x)=((6tan(x)+2))/(sec(x)) ?
The solution for f^'(x)=((6tan(x)+2))/(sec(x)) is f(x)=-6cos(x)+2sin(x)+c_{1}