What is area y=x^3-2x^2+3,y=3x^2+5x-22 ?

The answer to area y=x^3-2x^2+3,y=3x^2+5x-22 is (-75sqrt(5)+625)/3+75sqrt(5)-225

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area y=x^3-2x^2+3,y=3x^2+5x-22

area

y = x^{3} - 2 x^{2} + 3, y = 3 x^{2} + 5 x - 22

\frac{- 75 5 + 625}{3} + 755 - 225

Decimal Notation

95.13673 \dots

Solution steps

Apply the area formula:

\int_{- 5}^{5} x^{3} - 2 x^{2} + 3 - (3 x^{2} + 5 x - 22) d x

Solve

\int_{- 5}^{5} x^{3} - 2 x^{2} + 3 - (3 x^{2} + 5 x - 22) d x : \frac{- 75 5 + 625}{3} + 755 - 225

The area is:

= \frac{- 75 5 + 625}{3} + 755 - 225

y = x^{\frac{15}{14}}, y = 13 x^{\frac{1}{14}}

\frac{d}{d x} (x^{3} + 3 x)

\frac{d}{d x} ((\frac{1}{x ^{2}} - \frac{9}{x ^{4}}) (x + 3 x^{3}))

\int_{- 2}^{2} 4 - x^{2} d x

What is area y=x^3-2x^2+3,y=3x^2+5x-22 ?
The answer to area y=x^3-2x^2+3,y=3x^2+5x-22 is (-75sqrt(5)+625)/3+75sqrt(5)-225