What is the derivative of 2/(sqrt(x-3)) ?

The derivative of 2/(sqrt(x-3)) is -1/((x-3)^{3/2)}

What is the first derivative of 2/(sqrt(x-3)) ?

The first derivative of 2/(sqrt(x-3)) is -1/((x-3)^{3/2)}

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\frac{d}{d x} (\frac{2}{x - 3})

- \frac{1}{( x - 3 ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{2}{x - 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{x - 3})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((x - 3)^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( x - 3 ) ^{\frac{3}{2}}} \frac{d}{d x} (x - 3)

= - \frac{1}{2 ( x - 3 ) ^{\frac{3}{2}}} \frac{d}{d x} (x - 3)

\frac{d}{d x} (x - 3) = 1

= 2 (- \frac{1}{2 ( x - 3 ) ^{\frac{3}{2}}} \cdot 1)

Simplify

2 (- \frac{1}{2 ( x - 3 ) ^{\frac{3}{2}}} \cdot 1) : - \frac{1}{( x - 3 ) ^{\frac{3}{2}}}

= - \frac{1}{( x - 3 ) ^{\frac{3}{2}}}

\frac{d}{d x} ((\frac{x ^{2} + 1}{x ^{2} - 1})^{3})

\frac{\partial}{\partial x} (e^{x + 7 y})

y = (x^{2} + 7 x + 2)^{3}

y^{^{'}} = 8 \cdot \frac{2 + y}{x}, y (1) = 8

y = 6 cot (3 x)

What is the derivative of 2/(sqrt(x-3)) ?
The derivative of 2/(sqrt(x-3)) is -1/((x-3)^{3/2)}
What is the first derivative of 2/(sqrt(x-3)) ?
The first derivative of 2/(sqrt(x-3)) is -1/((x-3)^{3/2)}