What is the derivative of y=(x^2+7x+2)^3 ?

The derivative of y=(x^2+7x+2)^3 is 3(x^2+7x+2)^2(2x+7)

What is the first derivative of y=(x^2+7x+2)^3 ?

The first derivative of y=(x^2+7x+2)^3 is 3(x^2+7x+2)^2(2x+7)

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derivative of

y = (x^{2} + 7 x + 2)^{3}

3 (x^{2} + 7 x + 2)^{2} (2 x + 7)

Solution steps

\frac{d}{d x} ((x^{2} + 7 x + 2)^{3})

Apply the chain rule:

3 (x^{2} + 7 x + 2)^{2} \frac{d}{d x} (x^{2} + 7 x + 2)

= 3 (x^{2} + 7 x + 2)^{2} \frac{d}{d x} (x^{2} + 7 x + 2)

\frac{d}{d x} (x^{2} + 7 x + 2) = 2 x + 7

= 3 (x^{2} + 7 x + 2)^{2} (2 x + 7)

y^{^{'}} = 8 \cdot \frac{2 + y}{x}, y (1) = 8

y = 6 cot (3 x)

\frac{d}{d x} ((x - 6) (5 x + 1))

f (x) = \frac{- x ^{2} - 6}{( x ^{2} - 6 ) ^{2}}

\frac{\partial ^{2}}{\partial y ^{2}} (\frac{x y}{x - y})

What is the derivative of y=(x^2+7x+2)^3 ?
The derivative of y=(x^2+7x+2)^3 is 3(x^2+7x+2)^2(2x+7)
What is the first derivative of y=(x^2+7x+2)^3 ?
The first derivative of y=(x^2+7x+2)^3 is 3(x^2+7x+2)^2(2x+7)