What is the solution for (dy)/(dt)=y(10-y) ?

The solution for (dy)/(dt)=y(10-y) is y=(10)/(-e^{-10t-c_{1)}+1}

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(dy)/(dt)=y(10-y)

\frac{d y}{d t} = y (10 - y)

y = \frac{10}{- e ^{- 10 t - c_{1}} + 1}

Solution steps

\frac{d y}{d t} = y (10 - y)

Solve Bernoulli ODE:

y = \frac{10}{- e ^{- 10 t - c_{1}} + 1}

y = \frac{10}{- e ^{- 10 t - c_{1}} + 1}

\frac{\partial}{\partial x} (cos (θ))

y = - x - 1, x = - 1, x = 2, y = 0

\int_{0}^{π} x^{2} sin (2 x) d x

\frac{d}{d x} (a x^{2} + b - 4)

\frac{2 s + 1}{s ^{3} + 7 s ^{2} + 12 s}

What is the solution for (dy)/(dt)=y(10-y) ?
The solution for (dy)/(dt)=y(10-y) is y=(10)/(-e^{-10t-c_{1)}+1}