What is area e^{4x},e^{8x},x=1 ?

The answer to area e^{4x},e^{8x},x=1 is (e^8-2e^4+1)/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area e^{4x},e^{8x},x=1

area

e^{4 x}, e^{8 x}, x = 1

\frac{e ^{8} - 2 e ^{4} + 1}{8}

Decimal Notation

359.09521 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} e^{4 x} - e^{8 x} d x

Solve

\int_{0}^{1} e^{4 x} - e^{8 x} d x : \frac{e ^{8} - 2 e ^{4} + 1}{8}

The area is:

= \frac{e ^{8} - 2 e ^{4} + 1}{8}

(x^{2} + 1) y^{^{'}} + 6 x (y - 1) = 0

\frac{d}{d x} (\frac{5}{x} + x - 4)

\frac{d}{d x} ((\frac{5 x + 1}{2 x}) d x)

\frac{\partial}{\partial t} (2 r sin (t))

\frac{d}{d x} (x^{3} - 9 x^{2} + 10 x)

What is area e^{4x},e^{8x},x=1 ?
The answer to area e^{4x},e^{8x},x=1 is (e^8-2e^4+1)/8