What is taylor 8x^4-x^2+9x+2 ?

The answer to taylor 8x^4-x^2+9x+2 is 2+9x-x^2+8x^4

Popular >

taylor 8x^4-x^2+9x+2

taylor

8 x^{4} - x^{2} + 9 x + 2

2 + 9 x - x^{2} + 8 x^{4}

Solution steps

Apply the Taylor Formula

= 2 + \frac{\frac{d}{d x} ( 8 x ^{4} - x ^{2} + 9 x + 2 ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( 8 x ^{4} - x ^{2} + 9 x + 2 ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( 8 x ^{4} - x ^{2} + 9 x + 2 ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 2 + \frac{9}{1 !} x + \frac{- 2}{2 !} x^{2} + \frac{0}{3 !} x^{3} + \frac{192}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{0}{9 !} x^{9} + \frac{0}{10 !} x^{10}

Refine

= 2 + 9 x - x^{2} + 8 x^{4}

\int ln (11 x) d x

\frac{\partial}{\partial s} (s^{6} + t^{6})

\int_{0}^{2} π (x)^{2} d x

\frac{df}{d x} + 2 f = f x^{3}

\int_{5}^{6} \frac{1}{6 x - 1} d x

What is taylor 8x^4-x^2+9x+2 ?
The answer to taylor 8x^4-x^2+9x+2 is 2+9x-x^2+8x^4