What is the integral from 0 to 2 of pi(x)^2 ?

The integral from 0 to 2 of pi(x)^2 is (8pi)/3

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integral from 0 to 2 of pi(x)^2

\int_{0}^{2} π (x)^{2} d x

\frac{8 π}{3}

Decimal Notation

8.37758 \dots

Solution steps

\int_{0}^{2} π x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{0}^{2} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{2}

= π [\frac{x ^{3}}{3}]_{0}^{2}

Compute the boundaries:

\frac{8}{3}

= π \frac{8}{3}

Simplify

= \frac{8 π}{3}

\frac{df}{d x} + 2 f = f x^{3}

\int_{5}^{6} \frac{1}{6 x - 1} d x

n = 0 \sum \infty (\frac{1}{3})^{n}

\int \frac{3 t ^{2} + 3}{t - 1} d t

2 x^{2} + 3, x, (- 1, 2)

What is the integral from 0 to 2 of pi(x)^2 ?
The integral from 0 to 2 of pi(x)^2 is (8pi)/3