What is the solution for xy^'+y=-6xy^2,y(1)=9 ?

The solution for xy^'+y=-6xy^2,y(1)=9 is y= 9/(x(54ln(x)+1))

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xy^'+y=-6xy^2,y(1)=9

x y^{^{'}} + y = - 6 x y^{2}, y (1) = 9

y = \frac{9}{x ( 54 ln ( x ) + 1 )}

Solution steps

x y^{'} (x) + y = - 6 x y^{2}

Solve Bernoulli ODE:

y = \frac{9}{x ( 54 ln ( x ) + 1 )}

y = \frac{9}{x ( 54 ln ( x ) + 1 )}

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What is the solution for xy^'+y=-6xy^2,y(1)=9 ?
The solution for xy^'+y=-6xy^2,y(1)=9 is y= 9/(x(54ln(x)+1))