What is the integral of (-5sec^2(x)) ?

The integral of (-5sec^2(x)) is -5tan(x)+C

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integral of (-5sec^2(x))

\int (- 5 sec^{2} (x)) d x

- 5 tan (x) + C

Solution steps

\int - 5 sec^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 5 \cdot \int sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= - 5 tan (x)

Add a constant to the solution

= - 5 tan (x) + C

\int_{- 2}^{- 1} x^{- 3} d x

x \to 1 lim (\frac{1 - \frac{1}{x}}{1 - x})

\int_{0}^{π} sec^{2} (\frac{t}{3}) d t

y = x^{3}, (- 2, - 8)

What is the integral of (-5sec^2(x)) ?
The integral of (-5sec^2(x)) is -5tan(x)+C