What is the integral from-2 to-1 of x^{-3} ?

The integral from-2 to-1 of x^{-3} is -3/8

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integral from-2 to-1 of x^{-3}

\int_{- 2}^{- 1} x^{- 3} d x

- \frac{3}{8}

Decimal Notation

- 0.375

Solution steps

\int_{- 2}^{- 1} x^{- 3} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{- 2}^{- 1}

= [- \frac{1}{2 x ^{2}}]_{- 2}^{- 1}

Compute the boundaries:

- \frac{3}{8}

= - \frac{3}{8}

x \to 1 lim (\frac{1 - \frac{1}{x}}{1 - x})

\int_{0}^{π} sec^{2} (\frac{t}{3}) d t

y = x^{3}, (- 2, - 8)

n = 1 \sum \infty \frac{( - 3 ) ^{n}}{n}

What is the integral from-2 to-1 of x^{-3} ?
The integral from-2 to-1 of x^{-3} is -3/8