en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=2x^2-1,(0,1)

Solution

area

y = 2 x^{2} - 1, (0, 1)

Solution

\frac{2 2 - 1}{3}

+1

Decimal Notation

0.60947 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} 2 x^{2} - 1 d x

Solve

\int_{0}^{1} 2 x^{2} - 1 d x : \frac{2 2 - 1}{3}

The area is:

= \frac{2 2 - 1}{3}

Popular Examples

limit as x approaches 4 of 4x^2+5x+1

x \to 4 lim (4 x^{2} + 5 x + 1)

derivative of 3x+3

\frac{d}{d x} (3 x + 3)

limit as x approaches 0 of x/(sin(x/4))

x \to 0 lim (\frac{x}{sin ( \frac{x}{4} )})

derivative of e^x-2-x

\frac{d}{d x} (e^{x} - 2 - x)

y^'-9/x y=(y^4)/(x^{13)},y(1)=1

y^{^{'}} - \frac{9}{x} y = \frac{y ^{4}}{x ^{13}}, y (1) = 1

Frequently Asked Questions (FAQ)

What is area y=2x^2-1,(0,1) ?
The answer to area y=2x^2-1,(0,1) is (2sqrt(2)-1)/3