What is the derivative of (-x^2-4)/((x^2-4)^2) ?

The derivative of (-x^2-4)/((x^2-4)^2) is -(2x(-x^2-12))/((x^2-4)^3)

What is the first derivative of (-x^2-4)/((x^2-4)^2) ?

The first derivative of (-x^2-4)/((x^2-4)^2) is -(2x(-x^2-12))/((x^2-4)^3)

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derivative of

\frac{- x ^{2} - 4}{( x ^{2} - 4 ) ^{2}}

- \frac{2 x ( - x ^{2} - 12 )}{( x ^{2} - 4 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{- x ^{2} - 4}{( x ^{2} - 4 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( - x ^{2} - 4 ) ( x ^{2} - 4 ) ^{2} - \frac{d}{d x} ( ( x ^{2} - 4 ) ^{2} ) ( - x ^{2} - 4 )}{( ( x ^{2} - 4 ) ^{2} ) ^{2}}

\frac{d}{d x} (- x^{2} - 4) = - 2 x

\frac{d}{d x} ((x^{2} - 4)^{2}) = 4 x (x^{2} - 4)

= \frac{( - 2 x ) ( x ^{2} - 4 ) ^{2} - 4 x ( x ^{2} - 4 ) ( - x ^{2} - 4 )}{( ( x ^{2} - 4 ) ^{2} ) ^{2}}

Simplify

\frac{( - 2 x ) ( x ^{2} - 4 ) ^{2} - 4 x ( x ^{2} - 4 ) ( - x ^{2} - 4 )}{( ( x ^{2} - 4 ) ^{2} ) ^{2}} : - \frac{2 x ( - x ^{2} - 12 )}{( x ^{2} - 4 ) ^{3}}

= - \frac{2 x ( - x ^{2} - 12 )}{( x ^{2} - 4 ) ^{3}}

n = 0 \sum \infty \frac{1}{( 1 + n ^{2} )}

t^{- 2}

n = 0 \sum \infty \frac{1}{7 ^{n}}

\frac{d y}{d x} = \frac{( x + sec ^{2} ( x ) )}{y}

\int \frac{1}{1 + e ^{a x}} d x

What is the derivative of (-x^2-4)/((x^2-4)^2) ?
The derivative of (-x^2-4)/((x^2-4)^2) is -(2x(-x^2-12))/((x^2-4)^3)
What is the first derivative of (-x^2-4)/((x^2-4)^2) ?
The first derivative of (-x^2-4)/((x^2-4)^2) is -(2x(-x^2-12))/((x^2-4)^3)