What is (\partial}{\partial x}(\frac{x^3y^3)/3) ?

The answer to (\partial}{\partial x}(\frac{x^3y^3)/3) is x^2y^3

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(\partial}{\partial x}(\frac{x^3y^3)/3)

\frac{\partial}{\partial x} (\frac{x ^{3} y ^{3}}{3})

x^{2} y^{3}

Solution steps

\frac{\partial}{\partial x} (\frac{x ^{3} y ^{3}}{3})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{y ^{3}}{3} \frac{\partial}{\partial x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{y ^{3}}{3} \cdot 3 x^{3 - 1}

Simplify

\frac{y ^{3}}{3} \cdot 3 x^{3 - 1} : x^{2} y^{3}

= x^{2} y^{3}

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What is (\partial}{\partial x}(\frac{x^3y^3)/3) ?
The answer to (\partial}{\partial x}(\frac{x^3y^3)/3) is x^2y^3