What is (\partial)/(\partial x)(7cos(x)sin(y)) ?

The answer to (\partial)/(\partial x)(7cos(x)sin(y)) is -7sin(x)sin(y)

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(\partial)/(\partial x)(7cos(x)sin(y))

\frac{\partial}{\partial x} (7 cos (x) sin (y))

- 7 sin (x) sin (y)

Solution steps

\frac{\partial}{\partial x} (7 cos (x) sin (y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 sin (y) \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= 7 sin (y) (- sin (x))

Simplify

= - 7 sin (x) sin (y)

\frac{d}{d x} (\frac{e ^{3 x}}{x})

\frac{d}{d x} (ln (8 - 4 x))

\frac{d}{d x} (cos (x + e^{x}))

\frac{d}{d x} (\frac{x ^{2} + 4}{5 x - 9})

y^{^{''}} - 4 y^{^{'}} + 3 y = 0, y (0) = - 7.5, y^{^{'}} (0) = \frac{23}{5}

What is (\partial)/(\partial x)(7cos(x)sin(y)) ?
The answer to (\partial)/(\partial x)(7cos(x)sin(y)) is -7sin(x)sin(y)