What is the derivative of y=(4-3x^2)^3 ?

The derivative of y=(4-3x^2)^3 is -18x(4-3x^2)^2

What is the first derivative of y=(4-3x^2)^3 ?

The first derivative of y=(4-3x^2)^3 is -18x(4-3x^2)^2

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derivative of

y = (4 - 3 x^{2})^{3}

- 18 x (4 - 3 x^{2})^{2}

Solution steps

\frac{d}{d x} ((4 - 3 x^{2})^{3})

Apply the chain rule:

3 (4 - 3 x^{2})^{2} \frac{d}{d x} (4 - 3 x^{2})

= 3 (4 - 3 x^{2})^{2} \frac{d}{d x} (4 - 3 x^{2})

\frac{d}{d x} (4 - 3 x^{2}) = - 6 x

= 3 (4 - 3 x^{2})^{2} (- 6 x)

Simplify

= - 18 x (4 - 3 x^{2})^{2}

y^{^{'}} + 2 y = 10

\frac{d}{d x} (\frac{1}{27} (2 x - 1)^{3} (6 - 3 x) + 1)

\int_{0}^{\frac{π}{4}} sin (4 x) d x

\frac{- 3}{( s - 1 ) ^{2}}

f (x) = \frac{x ^{3}}{3} + 4 x^{2} + 12 x + 19

What is the derivative of y=(4-3x^2)^3 ?
The derivative of y=(4-3x^2)^3 is -18x(4-3x^2)^2
What is the first derivative of y=(4-3x^2)^3 ?
The first derivative of y=(4-3x^2)^3 is -18x(4-3x^2)^2