What is the derivative of 2sin(-x) ?

The derivative of 2sin(-x) is -2cos(x)

What is the first derivative of 2sin(-x) ?

The first derivative of 2sin(-x) is -2cos(x)

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\frac{d}{d x} (2 sin (- x))

- 2 cos (x)

Solution steps

\frac{d}{d x} (2 sin (- x))

Simplify

2 sin (- x) : - 2 sin (x)

= \frac{d}{d x} (- 2 sin (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (sin (x))

Apply the common derivative:

\frac{d}{d x} (sin (x)) = cos (x)

= - 2 cos (x)

34 (3 p + 1)^{- \frac{2}{5}}

\int \frac{2 x}{x ^{2} + 1} d x

\frac{1}{s ( s ^{2} + 25 )}

y = 4 tan (x), at x = \frac{π}{3}

\frac{d}{d x} (\frac{h ( x )}{x}) x = 2

What is the derivative of 2sin(-x) ?
The derivative of 2sin(-x) is -2cos(x)
What is the first derivative of 2sin(-x) ?
The first derivative of 2sin(-x) is -2cos(x)