What is the tangent of f(x)=x^2-5x+5,(4,1) ?

The tangent of f(x)=x^2-5x+5,(4,1) is y=3x-11

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tangent of f(x)=x^2-5x+5,(4,1)

tangent of

f (x) = x^{2} - 5 x + 5, (4, 1)

y = 3 x - 11

Solution steps

Find the slope of

f (x) = x^{2} - 5 x + 5 : \frac{df ( x )}{d x} = 2 x - 5

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 3

Find the line with slope m=

3

and passing through

(4, 1) : y = 3 x - 11

y = 3 x - 11

\int \frac{d}{1} (e^{x} cos (x)) d x

\frac{d}{d x} (\frac{1}{35} x^{5} + \frac{1}{4} x^{4} + x + 1)

f (x) = 8 x 16 + 0.5 x

\int_{2}^{5} \frac{x}{3} d x

n = 0 \sum \infty (1 + \frac{1}{n})^{n}

What is the tangent of f(x)=x^2-5x+5,(4,1) ?
The tangent of f(x)=x^2-5x+5,(4,1) is y=3x-11