What is the derivative of f(x)=9^x+e^x ?

The derivative of f(x)=9^x+e^x is 2ln(3)*9^x+e^x

What is the first derivative of f(x)=9^x+e^x ?

The first derivative of f(x)=9^x+e^x is 2ln(3)*9^x+e^x

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derivative of

f (x) = 9^{x} + e^{x}

2 ln (3) \cdot 9^{x} + e^{x}

Solution steps

\frac{d}{d x} (9^{x} + e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9^{x}) + \frac{d}{d x} (e^{x})

\frac{d}{d x} (9^{x}) = 2 ln (3) \cdot 9^{x}

\frac{d}{d x} (e^{x}) = e^{x}

= 2 ln (3) \cdot 9^{x} + e^{x}

x^{3}, - 2

tan (x)

n = 1 \sum \infty \frac{n !}{e ^{n}}

f (x) = \frac{2}{x}, (- 8, - \frac{1}{4})

\frac{8 x}{1 - tan ( x )}

What is the derivative of f(x)=9^x+e^x ?
The derivative of f(x)=9^x+e^x is 2ln(3)*9^x+e^x
What is the first derivative of f(x)=9^x+e^x ?
The first derivative of f(x)=9^x+e^x is 2ln(3)*9^x+e^x