What is the sum from n=0 to infinity of 9(5/12)^n ?

The sum from n=0 to infinity of 9(5/12)^n is 108/7

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sum from n=0 to infinity of 9(5/12)^n

n = 0 \sum \infty 9 (\frac{5}{12})^{n}

\frac{108}{7}

Solution steps

n = 0 \sum \infty 9 (\frac{5}{12})^{n}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 9 \cdot n = 0 \sum \infty (\frac{5}{12})^{n}

Apply Series Geometric Test:

\frac{12}{7}

= 9 \cdot \frac{12}{7}

Simplify

9 \cdot \frac{12}{7} : \frac{108}{7}

= \frac{108}{7}

\frac{d}{d x} ((x^{2} + 1)^{\frac{1}{2}})

f (x) = (ln (x))^{2}, at (x = 11)

n = 1 \sum \infty 2 n

\frac{d y}{d x} - (2 + y) x^{2} = 0

\frac{\partial}{\partial x} (tan (x^{2} + y))

What is the sum from n=0 to infinity of 9(5/12)^n ?
The sum from n=0 to infinity of 9(5/12)^n is 108/7