What is the solution for (dy)/(dx)-(2+y)x^2=0 ?

The solution for (dy)/(dx)-(2+y)x^2=0 is y=e^{(x^3)/3+c_{1}}-2

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(dy)/(dx)-(2+y)x^2=0

\frac{d y}{d x} - (2 + y) x^{2} = 0

y = e^{\frac{x ^{3}}{3} + c_{1}} - 2

Solution steps

\frac{d y}{d x} - (2 + y) x^{2} = 0

Solve separable ODE:

y = e^{\frac{x ^{3}}{3} + c_{1}} - 2

y = e^{\frac{x ^{3}}{3} + c_{1}} - 2

\frac{\partial}{\partial x} (tan (x^{2} + y))

y = sin (x), y = cos (x), x = \frac{5 π}{4}, x = 2 π

y = \frac{2 x}{x + 2}, (2, 1)

\frac{d}{d x} ((4^{x})^{9})

x \to \infty + lim (\frac{1}{0})

What is the solution for (dy)/(dx)-(2+y)x^2=0 ?
The solution for (dy)/(dx)-(2+y)x^2=0 is y=e^{(x^3)/3+c_{1}}-2