What is the solution for (dx}{dt}=\frac{2x)/t ,x(3)=1 ?

The solution for (dx}{dt}=\frac{2x)/t ,x(3)=1 is x=(t^2)/9

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(dx}{dt}=\frac{2x)/t ,x(3)=1

\frac{d x}{d t} = \frac{2 x}{t}, x (3) = 1

x = \frac{t ^{2}}{9}

Solution steps

\frac{d x}{d t} = \frac{2 x}{t}

Solve separable ODE:

x = \frac{t ^{2}}{9}

x = \frac{t ^{2}}{9}

f (x) = 5 e^{x} + 3 x, (0, 5)

10 + t^{2}

\frac{\partial}{\partial z} (- y e^{z^{3} + z^{2} + 1})

\int_{0}^{π} sin^{2} (7 x) d x

n = 1 \sum \infty \frac{3 ^{n}}{n ^{2}}

What is the solution for (dx}{dt}=\frac{2x)/t ,x(3)=1 ?
The solution for (dx}{dt}=\frac{2x)/t ,x(3)=1 is x=(t^2)/9