What is the tangent of f(x)=5e^x+3x,(0,5) ?

The tangent of f(x)=5e^x+3x,(0,5) is y=8x+5

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tangent of f(x)=5e^x+3x,(0,5)

tangent of

f (x) = 5 e^{x} + 3 x, (0, 5)

y = 8 x + 5

Solution steps

Find the slope of

f (x) = 5 e^{x} + 3 x : \frac{df ( x )}{d x} = 5 e^{x} + 3

Compute the slope of

f (x) = 5 e^{x} + 3 x

(0, 5) : m = 8

Find the line with slope m=

8

and passing through

(0, 5) : y = 8 x + 5

y = 8 x + 5

10 + t^{2}

\frac{\partial}{\partial z} (- y e^{z^{3} + z^{2} + 1})

\int_{0}^{π} sin^{2} (7 x) d x

n = 1 \sum \infty \frac{3 ^{n}}{n ^{2}}

\int - sec^{2} (x) d x

What is the tangent of f(x)=5e^x+3x,(0,5) ?
The tangent of f(x)=5e^x+3x,(0,5) is y=8x+5