What is the sum from n=0 to infinity of 4-sin(n) ?

The sum from n=0 to infinity of 4-sin(n) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of 4-sin(n)

n = 0 \sum \infty 4 - sin (n)

diverges

Solution steps

n = 0 \sum \infty 4 - sin (n)

Apply Series Divergence Test:

diverges

= diverges

\int_{0}^{2} \frac{1}{e ^{π x}} d x

\frac{d y}{d x} + 4 y = e^{- 4 x}

\frac{\partial}{\partial x} (3 x^{2} - 3)

\frac{d}{d x} (a^{2} arcsin (\frac{x}{a}))

\int \frac{x - 1}{x ^{2} ( x + 1 ) ^{2}} d x

What is the sum from n=0 to infinity of 4-sin(n) ?
The sum from n=0 to infinity of 4-sin(n) is diverges