What is (\partial)/(\partial x)(3x^2-3) ?

The answer to (\partial)/(\partial x)(3x^2-3) is 6x

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(\partial)/(\partial x)(3x^2-3)

\frac{\partial}{\partial x} (3 x^{2} - 3)

6 x

Solution steps

\frac{\partial}{\partial x} (3 x^{2} - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) - \frac{\partial}{\partial x} (3)

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (3) = 0

= 6 x - 0

Simplify

= 6 x

\frac{d}{d x} (a^{2} arcsin (\frac{x}{a}))

\int \frac{x - 1}{x ^{2} ( x + 1 ) ^{2}} d x

y^{2} d y + x^{3} d x = 0

f (x) = \frac{7}{x ^{2}} - 6 x^{2}, at x = 5

\frac{d}{d x} (2 x^{2} + 1)

What is (\partial)/(\partial x)(3x^2-3) ?
The answer to (\partial)/(\partial x)(3x^2-3) is 6x