What is the solution for (dy)/(dx)+4y=e^{-4x} ?

The solution for (dy)/(dx)+4y=e^{-4x} is y= x/(e^{4x)}+(c_{1})/(e^{4x)}

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(dy)/(dx)+4y=e^{-4x}

\frac{d y}{d x} + 4 y = e^{- 4 x}

y = \frac{x}{e ^{4 x}} + \frac{c _{1}}{e ^{4 x}}

Solution steps

\frac{d y}{d x} + 4 y = e^{- 4 x}

Solve linear ODE:

y = \frac{x}{e ^{4 x}} + \frac{c _{1}}{e ^{4 x}}

y = \frac{x}{e ^{4 x}} + \frac{c _{1}}{e ^{4 x}}

\frac{\partial}{\partial x} (3 x^{2} - 3)

\frac{d}{d x} (a^{2} arcsin (\frac{x}{a}))

\int \frac{x - 1}{x ^{2} ( x + 1 ) ^{2}} d x

y^{2} d y + x^{3} d x = 0

f (x) = \frac{7}{x ^{2}} - 6 x^{2}, at x = 5

What is the solution for (dy)/(dx)+4y=e^{-4x} ?
The solution for (dy)/(dx)+4y=e^{-4x} is y= x/(e^{4x)}+(c_{1})/(e^{4x)}