What is (\partial)/(\partial x)(xycos(yz)) ?

The answer to (\partial)/(\partial x)(xycos(yz)) is ycos(yz)

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(\partial)/(\partial x)(xycos(yz))

\frac{\partial}{\partial x} (x y cos (yz))

y cos (yz)

Solution steps

\frac{\partial}{\partial x} (x y cos (yz))

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y cos (yz) \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= y cos (yz) \cdot 1

Simplify

= y cos (yz)

\frac{d}{d x} (ln (\frac{x ^{2} - 1}{x ^{2} + 1}))

a^{2} x^{2} + b^{2}

y = (\frac{( x ^{2} + 8 )}{x ^{2} - 8})

3 t^{2} + 13 t + 13

What is (\partial)/(\partial x)(xycos(yz)) ?
The answer to (\partial)/(\partial x)(xycos(yz)) is ycos(yz)