What is the derivative of x^4-8x^3 ?

The derivative of x^4-8x^3 is 4x^3-24x^2

What is the first derivative of x^4-8x^3 ?

The first derivative of x^4-8x^3 is 4x^3-24x^2

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derivative of

x^{4} - 8 x^{3}

4 x^{3} - 24 x^{2}

Solution steps

\frac{d}{d x} (x^{4} - 8 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (8 x^{3})

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (8 x^{3}) = 24 x^{2}

= 4 x^{3} - 24 x^{2}

\frac{\partial}{\partial x} (\frac{3}{3 x + 2 y})

\frac{d y}{d x} = \frac{x y + x ^{2} + y ^{2}}{x ^{2}}

\frac{d}{d x} (3 x^{3} - 4)

8 e^{2 x}

\int e^{- x} - e^{x} d x

What is the derivative of x^4-8x^3 ?
The derivative of x^4-8x^3 is 4x^3-24x^2
What is the first derivative of x^4-8x^3 ?
The first derivative of x^4-8x^3 is 4x^3-24x^2