What is the limit as x approaches 8 of 1/((x-8)^2) ?

The limit as x approaches 8 of 1/((x-8)^2) is infinity

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limit as x approaches 8 of 1/((x-8)^2)

x \to 8 lim (\frac{1}{( x - 8 ) ^{2}})

\infty

Solution steps

x \to 8 lim (\frac{1}{( x - 8 ) ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 8 - lim (\frac{1}{( x - 8 ) ^{2}}) = \infty

x \to 8 + lim (\frac{1}{( x - 8 ) ^{2}}) = \infty

= \infty

\int \frac{( tan ^{3} ( ln ( x ) ) )}{3 x} d x

(4 x + 5)^{5}, at x = - 1

\frac{d}{d x} (\frac{e ^{x}}{8 x ^{2} + 1})

csc (y) d x + sec (x) d y = 0

f (x) = e^{2 x} arcsin (x)

What is the limit as x approaches 8 of 1/((x-8)^2) ?
The limit as x approaches 8 of 1/((x-8)^2) is infinity