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Popular >

y^'=3x+y,y(0)=5

Solution

y^{^{'}} = 3 x + y, y (0) = 5

Solution

y = - 3 (x + 1) + 8 e^{x}

Solution steps

y^{'} (x) = 3 x + y

Solve linear ODE:

y = - 3 (x + 1) + 8 e^{x}

y = - 3 (x + 1) + 8 e^{x}

Popular Examples

integral from 0 to 1 of x/(x^2+4x+13)

\int_{0}^{1} \frac{x}{x ^{2} + 4 x + 13} d x

tangent of y=2sqrt(x),(1,2)tangent of

y = 2 x, (1, 2)

derivative of y=(x^4)/(16)derivative of

y = \frac{x ^{4}}{16}

integral of x(3x-5)^{10}

\int x (3 x - 5)^{10} d x

integral of 1/((x)ln(x))

\int \frac{1}{( x ) ln ( x )} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=3x+y,y(0)=5 ?
The solution for y^'=3x+y,y(0)=5 is y=-3(x+1)+8e^x