What is the solution for (y^4x)(dy)/(dx)=1+x,y(1)=2 ?

The solution for (y^4x)(dy)/(dx)=1+x,y(1)=2 is y=\sqrt[5]{5ln(x)+5x+27}

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(y^4x)(dy)/(dx)=1+x,y(1)=2

(y^{4} x) \frac{d y}{d x} = 1 + x, y (1) = 2

Solution steps

(y^{4} x) \frac{d y}{d x} = 1 + x

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What is the solution for (y^4x)(dy)/(dx)=1+x,y(1)=2 ?
The solution for (y^4x)(dy)/(dx)=1+x,y(1)=2 is y=\sqrt[5]{5ln(x)+5x+27}